-16x^2+70x=76

Solution for -16x^2+70x=76 equation:

-16x^2+70x=76

We move all terms to the left:

-16x^2+70x-(76)=0

a = -16; b = 70; c = -76;
Δ = b2-4ac
Δ = 702-4·(-16)·(-76)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-6}{2*-16}=\frac{-76}{-32}
=2+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+6}{2*-16}=\frac{-64}{-32}
=+2
$